Chemistry Tutoring

Chemistry changes shape as you move up. In high school it is mostly mole math, balanced equations, and the periodic table. In general chemistry it becomes equilibrium and energy. Organic chemistry turns into a course about mechanisms, and the upper-level courses lean on heavy math or abstract theory. It can feel like starting over each time, but the same ideas keep coming back: counting particles, tracking energy, and following electrons. STEM Tutor 360 offers one-on-one tutoring at every stage, so your tutor can spot when a shaky idea from an earlier course is causing trouble in this one.

Each session follows your own class: the syllabus, the homework, the practice exams, and your test dates. You work problems on a shared whiteboard, and you do much of the writing. Sessions run 1 to 2 hours, and you buy hours as a package and use them when you need them. A free consultation is available if you want to talk through your class before booking any hours.

Find your chemistry course

Not sure where to begin? Find your course below. Each one has its own page, linked at the bottom of this page, with a worked example and the places students usually slip. Chemical engineering majors often need several of these courses, plus process courses of their own.

• High school chemistry: on-level, honors, and pre-AP, with help on lab reports and unit tests.
• AP Chemistry: the nine College Board units and free-response practice.
• General chemistry: college General Chemistry I and II, including equilibrium and thermodynamics.
• Organic chemistry: Organic I and II, with arrow-pushing mechanisms and spectroscopy.
• Biochemistry: proteins, enzymes, and metabolism, with overlap for MCAT review.
• Physical chemistry: thermodynamics, kinetics, and quantum mechanics, with calculus support.
• Analytical chemistry: statistics, calibration, titrations, and instrumental methods.
• Inorganic chemistry: symmetry, molecular orbitals, coordination compounds, and solids.

A typical chemistry problem, worked

This kind of problem shows up in every course, and one habit solves it. A student needs 250.0 mL of 0.150 M sodium chloride solution. How many grams of $\ce{NaCl}$ should be weighed out? Then 10.00 mL of that solution is diluted to 100.0 mL. What is the new concentration?

Molarity means moles per liter, so find the moles first: $0.150\ \text{mol/L} \times 0.2500\ \text{L} = 0.0375\ \text{mol}$. The molar mass of $\ce{NaCl}$ is 58.44 g/mol (22.99 for $\ce{Na}$ plus 35.45 for $\ce{Cl}$), so $0.0375\ \text{mol} \times 58.44\ \text{g/mol} = 2.19\ \text{g}$.

For the dilution, the moles of $\ce{NaCl}$ do not change. Only the volume does. The new concentration is $0.150\ \text{M} \times \left(\dfrac{10.00\ \text{mL}}{100.0\ \text{mL}}\right) = 0.0150\ \text{M}$.

The habit is to write the units, let them point to the next step, and check that the answer is a sensible size. It carries from the first mole problem in high school to buffers, rate constants, and enzyme assays.