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    Thermodynamics Tutoring

    One-on-one thermo help that turns property tables, entropy, and cycle analysis from a nightmare into a procedure.

    Thermodynamics has a reputation problem for good reason: it's the first engineering course where the difficulty isn't the equations — it's knowing what kind of system you're looking at. Closed or open? Ideal gas or two-phase? Which table, which interpolation, which form of the first law? Students drown in bookkeeping before they ever get to the physics. STEM Tutor 360 teaches a fixed analysis procedure — define the system, list states, find properties, apply the balance laws — that works on every problem in the course.

    Sessions cover properties of pure substances and the art of reading steam tables, first-law analysis of closed systems and control volumes (turbines, pumps, nozzles, heat exchangers), the second law and entropy, and the cycle analysis — Rankine, Brayton, refrigeration — that dominates the back half of the semester.

    What We Cover

    Property tables, quality, and two-phase mixtures without the confusion
    First law for closed systems and control volumes
    Turbines, compressors, nozzles, throttles, and heat exchangers
    Second law, entropy, and isentropic efficiency
    Rankine, Brayton, Otto, Diesel, and refrigeration cycles

    A typical thermo problem, worked

    An ideal Rankine cycle: steam enters the turbine at 8 MPa and 500°C, and the condenser runs at 10 kPa. Find the thermal efficiency. This is the problem that decides most Thermo I finals, and it is exactly the kind of steam table work students ask for help with.

    State 1 is saturated liquid leaving the condenser at 10 kPa, so h1=191.8 kJ/kgh_1 = 191.8\ \text{kJ/kg} and v1=0.00101 m3/kgv_1 = 0.00101\ \text{m}^3\text{/kg}. The pump work is v1v_1 times the pressure rise: 0.00101×(8000−10)=8.1 kJ/kg0.00101 \times (8000 - 10) = 8.1\ \text{kJ/kg}, so h2=199.9 kJ/kgh_2 = 199.9\ \text{kJ/kg}.

    State 3 comes from the superheated table at 8 MPa and 500°C: h3=3399.5 kJ/kgh_3 = 3399.5\ \text{kJ/kg} and s3=6.7266 kJ/kg⋅Ks_3 = 6.7266\ \text{kJ/kg}\cdot\text{K}. The turbine is isentropic, so s4=s3s_4 = s_3 at 10 kPa. That entropy falls between sf=0.6492s_f = 0.6492 and sg=8.1489s_g = 8.1489, which tells you state 4 is a two-phase mixture. The quality is x4=6.7266−0.64927.4996=0.810x_4 = \dfrac{6.7266 - 0.6492}{7.4996} = 0.810 so h4=191.8+0.810×2392.1=2130.3 kJ/kgh_4 = 191.8 + 0.810 \times 2392.1 = 2130.3\ \text{kJ/kg}

    Turbine work is h3−h4=1269.2 kJ/kgh_3 - h_4 = 1269.2\ \text{kJ/kg} and heat in is h3−h2=3199.6 kJ/kgh_3 - h_2 = 3199.6\ \text{kJ/kg}. Net work is 1269.2−8.1=1261.1 kJ/kg1269.2 - 8.1 = 1261.1\ \text{kJ/kg}, so the efficiency is 1261.13199.6=39.4%\dfrac{1261.1}{3199.6} = 39.4\%.

    Notice what did the work: listing four states, checking the phase before touching a table, and applying one balance per device. The same procedure handles reheat, regeneration, and every other cycle in the course. Your textbook's tables may differ in the last digit depending on the edition.

    How the course usually runs

    Whether your class uses Cengel & Boles, Moran & Shapiro, or Borgnakke & Sonntag, Thermo I and II cover the same ground in roughly this order. I follow your book's notation and sign convention, since those are what your grader expects.

    • Properties of pure substances: phase diagrams, quality, and reading the steam and refrigerant tables
    • Energy and the first law for closed systems: boundary work, specific heats, and ideal gases
    • Mass and energy balances for control volumes: nozzles, turbines, pumps, throttles, and heat exchangers
    • The second law, heat engines, refrigerators, and the Carnot limits
    • Entropy, isentropic processes, and isentropic efficiency
    • Thermo II: gas and vapor power cycles, refrigeration cycles, exergy, gas mixtures, psychrometrics, and combustion

    Where students get stuck

    • Opening a table before checking the phase. Two independent properties and a comparison against the saturation values come first.
    • Heat and work sign conventions, which differ between textbooks and flip answers.
    • Using internal energy where a control volume needs enthalpy, or the reverse.
    • Treating the isentropic exit state as the actual one when the problem gives a device efficiency.
    • Interpolation slips and unit mismatches, especially kPa against MPa and kJ against J.

    Stuck on thermodynamics homework?

    Most thermodynamics homework help requests come down to setup: which system, which states, which table. In a session we work a similar problem step by step until the procedure makes sense, then you solve your own with me checking your reasoning as you go.

    I won't complete graded work for you. It wouldn't help on the exam, and the exam is where the grade is decided. Sessions are 60 minutes, online on a shared whiteboard, and it helps to send the problem set and your syllabus beforehand.

    Book a free 15-minute consultation

    Who this is for

    Mechanical, aerospace, and chemical engineering students in Thermodynamics I or II at any university — online sessions with a shared whiteboard serve students at UH, Texas A&M, UT Austin, and nationwide. In-person available around Richmond, Sugar Land, and Katy, TX. Thermo is also one of the most-failed FE exam topics, and review sessions can target it directly.

    Why STEM Tutor 360

    Engineer-Led

    Every session is taught by a Georgia Tech mechanical engineering graduate — not a rotating roster of contractors.

    One-on-One

    Fully personalized sessions built on a diagnostic of your student's actual strengths and gaps.

    Local & Online

    In-person sessions across Richmond, Sugar Land, and Katy, or online with a shared whiteboard — evenings and weekends.

    Frequently Asked Questions

    Ready to Get Started?

    Book a free consultation and get an honest assessment of where your student stands and a concrete plan to improve — no commitment required.

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